Question

A weather balloon is filled with 1000 mol of He gas at `25"^o`C and 101 kPa of pressure. What is the volume of the weather balloon?

Answer 1

`V=(nRT)/P~=25*m^3`

Explanation:

`V=(10^3*molxx0.0821*L*atm*K^-1*mol^-1xx298*K)/(1*atm)`

Note that `101*kPa~=1*atm`

We get `V=24.4xx10^3L=24.4*m^3`.

What is the mass of the gas inside the balloon? Will it float in air?

This problem reminds me of an old story, that of Lawnchair Larry, who luckily survived the experience. Many Darwin award winners don't!