Question

A wire has length of `0.83m` and mass `0.005kg` and resonates at `215`Hz. What is the tension of the wire?

Answer 1

`"767 Newton"`

Explanation:

`f = 1/(2l)sqrt[T/(m//L)]`

`"215 Hz" = 1/(2 × "0.83 m")sqrt[T/("0.005 kg / 0.83 m")]`

Square on both the sides

`215^2 = 1/(2 × 0.83)^2 × (0.83T)/0.005`

`T = [(215 × 2 × 0.83)^2 × 0.005]/0.83 "N" = "767 N"`