# A worker pushes a wheelbarrow with a force 40N over a level distance 6m. Frictional force 24N acts on the wheelbarrow in opposite direction to that of the worker, find the net work done on wheelbarrow?

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#### Explanation

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#### Explanation:

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Gió Share
Aug 6, 2015

I found: $W = 96 J$

#### Explanation:

Considering the situation:

The net force will be:
${F}_{\text{net}} = \Delta F = {F}_{1} - f = 40 - 24 = 16 N$
the work done will then be:
$W = {F}_{\text{net}} \cdot s = 16 \cdot 6 = 96 J$

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