A worker pushes a wheelbarrow with a force 40N over a level distance 6m. Frictional force 24N acts on the wheelbarrow in opposite direction to that of the worker, find the net work done on wheelbarrow?

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Gió Share
Aug 6, 2015

Answer:

I found: #W=96J#

Explanation:

Considering the situation:
enter image source here
The net force will be:
#F_("net")=DeltaF=F_1-f=40-24=16N#
the work done will then be:
#W=F_("net")*s=16*6=96J#

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