Question

A worker pushes a wheelbarrow with a force 40N over a level distance 6m. Frictional force 24N acts on the wheelbarrow in opposite direction to that of the worker, find the net work done on wheelbarrow?

Answer 1

I found: `W=96J`

Explanation:

Considering the situation:

The net force will be:
`F_("net")=DeltaF=F_1-f=40-24=16N`
the work done will then be:
`W=F_("net")*s=16*6=96J`