A yield of #NH_3# of approximately 98% can be obtained at 200 deg C and 1,000 atmospheres of pressure. How many grams of #N_2# must react to form 1.7 grams of ammonia, #NH_3#?
1.429 g of
We always have to read the problems completely to understand the question. In this case even when we have pressure and temperature conditions specified, they don't matter, first because they are constant and in second because the question ask for grams of
We cannot compare grams of a substance to another in chemical reactions, we need to use moles, then we have to convert the weight of NH3 to moles.
The yield is 98%, then the number of moles that would be produced are:
From the reaction (the hydrogen was implicit in the problem, because you are obtaining
There are 2 parts of
Then the moles of
Last step is too convert the moles back to grams using the MW of