A35.8 g sample of cadmium metal was melted by an electric heater providing 4.66 J/s of heat. If it took 6.92 min from the time the metal began to melt until it was completely melted, what is the heat of fusion per mole of cadmium?

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Answer 1 · 2017-11-26T21:22:46

This is a pretty creative problem.

#35.8g * (mol)/(112.4g) = 0.319mol#

of cadmium are melted.

#6.92min * (60s)/(min) * (4.66J)/s * (kJ)/(10^3J) approx 1.93kJ#

of heat were required, hence,

#(1.93kJ)/(0.319mol) approx (6.07kJ)/(mol)#

is the heat of fusion for cadmium, per the data under analysis.