A balloon has a volume of 2.9 L at 320 Kelvin. If the temperature is raised to 343 Kelvin, what will its volume be?

Jul 7, 2016

Using Charles' law, ${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$
Therefore ${V}_{2} = {T}_{2.} {V}_{1} / {T}_{1}$ = $343 . \frac{2.9}{320}$ = 3.11 litre.