Question

A balloon has a volume of 2.9 L at 320 Kelvin. If the temperature is raised to 343 Kelvin, what will its volume be?

Answer 1

3.11 litres

Explanation:

Using Charles' law, `V_1/T_1 = V_2/T_2`

Therefore `V_2 = T_2.V_1/T_1` = `343 . 2.9/320` = 3.11 litre.

However, this assumes that the material from which the balloon is made is sufficiently elastic to be able to stretch to accommodate the full increase in volume.