A balloon that had a volume of 3.50 L at 25.0 °C is placed in a hot room at 40.0 °C. If the pressure remains constant at 1.00 atm, what is the new volume of the balloon in the hot room?

1 Answer

Answer:

3.68 liters to three significant numbers.

Explanation:

This is a Charles Law problem

# V_1/T_1 = V_2/T_2#

# V_1 = "3.5 L"#,

# T_1 = 25 + 273 = "298 K"# ,

#V_2 = "unknown L"#,

# T_2 = 40 + 273 = "313 K"#,

so

# ("3.5 L")/("298 K") = V_2/("313 K")# .

This gives

# ("3.5 L") xx ("313 K")/("298 K") = V_2#.

#=> "3.68 L" = V_2#