Algebra fraction a^4/3 b^-1/3sqrta^-2 b^-2, where a>0 and b>0 ? answers A = 1/a^3b^4/3, B= a^2/b^1/3, C=a^2/b^7/3, D=a^4/b^1/3, E=a^4/b^7/3,

1 Answer
Jim G.
Dec 11, 2017

#a^(1/3)/b^(4/3)#

Explanation:

#"using the "color(blue)"laws of exponents"#

#•color(white)(x)a^-nhArr1/a^n#

#•color(white)(x)a^mxxa^nhArra^((m+n))#

#a^(4/3)b^(-1/3)sqrt(a^-2b^-2)#

#sqrt(a^-2b^-2)=sqrt(1/(a^2b^2))=1/(ab)=a^-1b^-1#

#rArra^(4/3)b^(-1/3)a^-1b^-1#

#=a^((4/3-1))b^((-1/3-1))#

#=a^(1/3)b^(-4/3#

#=a^(1/3)/b^(4/3)#

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