Question

Aluminum will react with sulfuric acid in the following reaction: `2Al(s) + 3H_2SO_4(l) -> Al_2(SO_4)_3(aq) + 3H_2(g)`. How many moles of `H_2SO_4` will react with 18 mol Al? How many moles of each product will be produced?

Answer 1

`=27molH_2SO_4`

Explanation:

With reference to the given balanced equation for the mole ratios, the needed number of moles for each remaining compound involved in the reaction using the mass of `Al` as basis for the molar conversions can be computed as;

`etaH_2SO_4:`
`=18cancel(molAl)xx(3molH_2SO_4)/(2cancel(molAl))`
`=27molH_2SO_4`

`etaAl_2(SO_4)_3:`
`=18cancel(molAl)xx(1molAl_2(SO_4)_3)/(2cancel(molAl))`
`=9molAl_2(SO_4)_3`

`etaH_2:`
`=18cancel(molAl)xx(3molH_2)/(2cancel(molAl))`
`=27molH_2`