Aluminum will react with sulfuric acid in the following reaction: #2Al(s) + 3H_2SO_4(l) -> Al_2(SO_4)_3(aq) + 3H_2(g)#. How many moles of #H_2SO_4# will react with 18 mol Al? How many moles of each product will be produced?

1 Answer
Jan 4, 2018

Answer:

#=27molH_2SO_4#

Explanation:

With reference to the given balanced equation for the mole ratios, the needed number of moles for each remaining compound involved in the reaction using the mass of #Al# as basis for the molar conversions can be computed as;

#etaH_2SO_4:#
#=18cancel(molAl)xx(3molH_2SO_4)/(2cancel(molAl))#
#=27molH_2SO_4#

#etaAl_2(SO_4)_3:#
#=18cancel(molAl)xx(1molAl_2(SO_4)_3)/(2cancel(molAl))#
#=9molAl_2(SO_4)_3#

#etaH_2:#
#=18cancel(molAl)xx(3molH_2)/(2cancel(molAl))#
#=27molH_2#