Question

An AC generator made of coil with area 1.0 square meters rotates in a 0.10 T magnetic field at a frequency of 50 Hz. Solve for the number of turns needed to generate a peak power voltage of 250 V ?

Answer 1

`8` turns

Explanation:

Voltage at time `"t"` is given as

`"V(t)" = -"NBAω"sin("ωt")`

Maximum (peak) voltage is

`"V"_@ = "NBAω"`

`"N" = ("V"_@) / ("BAω") = "250 V"/("0.1 T × 1.0 m"^2 × 2 π × "50 Hz") ≈ 8`