Question

)An Aeresol can with a volume of 325 mL contains gas at 445kPa at 12ºC. What volume would the gas occupy if it was allowed to escape at 101 kPa and 21ºC? (Answer is 1.5 x 10^3 mL) No matter what I try I can't get the answer right

Answer 1

`V_2~~1500ml`

Explanation:

Using the combined gas law...

`(P_1*V_1)/T_1` = `(P_2*V_2)/T_2`

Solve for `V_2` ...

`V_2=(P_1*V_1*T_2)/(T_1*P_2*)`

`P_1=445"KPa"color(white)(xxxxxxxxxxxxx)P_2=101KPa`
`V_1=325mlcolor(white)(xxxxxxxxxxxxxxx)V_2=?`
`T_1=(12+273)=285K"color(white)(xxxxxx)T_2=(21+273)=294K`

`V_2=(325ml*445cancel(KPa)*294cancel(K))/(101cancel(KPa)*285cancel(K))=1477ml~~1500ml`