# An airplane travelling horizontally at 406 km/h at a height of 2 km releases a bomb. How far ahead (to the nearest meter) from the release point does the bomb strike the ground?

Mar 6, 2016

2277 meters.

#### Explanation:

There is no horizontal component of acceleration, due to gravity.
Bomb speed, at release, is 406 km/h = $\frac{406}{3600}$km/s
If time between release and strike is t sec, horizontal distance of the target is $\left(\frac{406}{3600}\right) t$ km.
Vertical distance traveled is
2 km = $\left(\frac{1}{2}\right) \left(g\right) {t}^{2} = \left(\frac{1}{2}\right) \left(9.81 E - 02\right) {t}^{2}$
t = 20.193s, nearly..
x = 2.2773 km = 2277 meter, nearly.