An airplane travelling horizontally at 406 km/h at a height of 2 km releases a bomb. How far ahead (to the nearest meter) from the release point does the bomb strike the ground?

1 Answer
A. S. Adikesavan
Mar 6, 2016

2277 meters.

Explanation:

There is no horizontal component of acceleration, due to gravity.
Bomb speed, at release, is 406 km/h = #406/3600#km/s
If time between release and strike is t sec, horizontal distance of the target is #(406/3600)t# km.
Vertical distance traveled is
2 km = #(1/2)(g)t^2 = (1/2)(9.81 E-02)t^2#
t = 20.193s, nearly..
x = 2.2773 km = 2277 meter, nearly.

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