# An arrow is shot at a target 20 m away. The arrow is shot with a horizontal velocity of 60 m/s. How long is the arrow in the air for, and how far does the arrow drop as it approaches the target?

Nov 28, 2015

(a).

$0.33 \text{s}$

(b).

$0.53 \text{m}$

#### Explanation:

$\left(a\right) .$

The horizontal component of velocity is constant so we can say:

$t = \frac{s}{v} = \frac{20}{60} = 0.33 \text{s}$

$\left(b\right) .$

Now we use the vertical component of the arrow's motion:

$s = \frac{1}{2} \text{g} {t}^{2}$

$\therefore s = 0.5 \times 9.8 \times {0.33}^{2}$

$s = 0.53 \text{m}$