Question

An athlete stretches a spring an extra 35.7 cm beyond its initial length. How much energy has he transferred to the spring, if the spring constant is 56.8 N/cm?

Answer 1

`2028N`

Explanation:

We have to use Hooke's law, which states that

`F=kx`

`k` is the spring constant in `N"/"cm`

`x` is the extension in `cm`

Plugging in `x=35.7cm`, `k=56.8N"/"cm`, we have the force, which equals

`F=56.8N"/"cm*35.7cm=2027.76N~~2028N` to the nearest whole number.