Question

An average force of `6.00 xx 10^-3` `N` is required to move a `4.50 xx 10^-4` `C` charge from one point to another point that is `0.750` `m` away. The potential difference between the two points is?

Answer 1

The work done is given by `W=fd = 6.00xx10^-3xx0.750=4.5xx10^-3` `J`.

We also have `W=qV`, and can rearrange to `V=W/q = (4.5xx10^-3)/(4.5xx10^-4)=10` `V`