An egg is thrown off the top of a building. That height in meters above the ground is #h=300+2t-4.9t^2#, where #t# is the time since it was thrown in seconds and #h# is the height meters. How high is the egg above the ground after 5 seconds?

2 Answers
Narad T.
Dec 25, 2017

THe answer is #=187.5m#

Explanation:

The height is given by the equation

#h(t)=300+2t-4.9t^2#

When #t=5s#, we have

#h(5)=300+(2*5)-4.9*(5^2)#

#=300+10-122.5#

#=187.5m#

Anirudh E.
Dec 25, 2017

See below.

Explanation:

If at first you don't understand what a word problem is asking for, read, read again!

In order to solve this problem, we are given that the time (#t#) is #5# seconds. We are asked to find the corresponding height, #h# value.

So what you need to do is substitute #5# for #t# in the above equation and solve for #h#. I will leave this to you, as it shouldn't be too challenging.*

I hope that helps!

*Leave a comment if you are still struggling, and I will try to help you!

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