Question

An object is thrown horizontally from a height how does the time of flight and the range of the object change when the magnitude of initial velocity tripled?

Answer 1

When an object is thrown horizontally from constant height `h` with a velocity `u`,if it takes time `t` to reach the ground,considering vertical motion only,we can say,

`h=1/2g t^2` (using, `h=ut +1/2 g t^2` ,here`u=0` as initially no component of velocity was present vertically)

so,`t=sqrt((2h)/g)`

So,we can see this expression is independent of initial velocity `u`,so on tripling `u` there will be no effect on time of flight.

now,if it went upto `R` horizontally in this time,then we can say,its range of motion, `R=ut=sqrt((2h)/g)u` (as,`u` remains constant through out)

So,we can see,from the above expression that, `R prop u`

So,on tripling `u` range will also get tripled.