# An object is thrown upward from the ground with an initial velocity of 32ft/s. What is the maximum height the object obtains using the formula s = -16t^2 + 32t, where s = distance above the ground in feet, and t= time in seconds?

##### 1 Answer

Apr 14, 2015

The maximum height with respect to time will occur when the derivative of the distance(time) function equals

Maximum occurs when

When