# An object travels North at 4 m/s for 9 s and then travels South at 5 m/s for  2 s. What are the object's average speed and velocity?

Total distance covered by the object along north is $4 \cdot 9 m$ or $36 m$ and along south is $5 \cdot 2 m$ or $10 m$,hence total distance covered is $36 + 10$ or $46 m$
I.e $\frac{46}{11} \frac{m}{s}$ or $4.18 \frac{m}{s}$
And, average velocity= total displacement/total time I.e $\frac{10 - 36}{11}$ or $- 2.36 \frac{m}{s}$