An object with a mass of #160 g# is dropped into #880 mL# of water at #0^@C#. If the object cools by #18 ^@C# and the water warms by #8 ^@C#, what is the specific heat of the material that the object is made of?
1 Answer
Feb 8, 2016
Explanation:
Assumption : Specific gravity of water at
Now by Law of conservation of energy
Heat lost by object = Heat gained by water.
Also Heat gained or lost
where
Heat lost by object
Heat gained by water
(Specific heat of water in cgs units is 1 calorie/gm)
Equating two we obtain