An object with a mass of #160 g# is dropped into #880 mL# of water at #0^@C#. If the object cools by #120 ^@C# and the water warms by #5 ^@C#, what is the specific heat of the material that the object is made of?

1 Answer
Feb 3, 2016

Answer:

#1004.35jkg^(-1)K^(-1)#

Explanation:

suppose,
the specific heat of the object is #S#
now,
we know,
#1ml# water= #1gm#
#:.880ml# water=#880gm#
#=0.88kg#
and we know,
heat loss= heat gain
#0.16Sxx(120-5)=0.88xx4200xx5#
#=>18.4S=18480#
#=>S=1004.35jkg^(-1)K^(-1)#