An object with a mass of #18 g# is dropped into #240 mL# of water at #0^@C#. If the object cools by #120 ^@C# and the water warms by #6 ^@C#, what is the specific heat of the material that the object is made of?

1 Answer
Feb 5, 2016

Answer:

#"a"#)#c_o=0,0 bar 1##" specific heat of material"#
#"b"#)#"material may be made of iron"#

Explanation:

#"heat taken by water is:" Q_t=m_w.c_w. Delta t#
#"240 m L of water is 240 mg =0,24 g" " "c_w=1"#
#Q_t=0,24.1.(10-0)=2,4 Cal#
#" heat given by object is:"Q_o=m_o . c_o . Delta t_o#
#Q_o=18 . c_o .120=c_o .2160#
#c_o .2160=2,4#
#c_o=(2,4)/2160#
#"a"#)#c_o=0,0 bar 1##" specific heat of material"#
#"b"#)#"material may be made of iron"#