# An object with a mass of #2 kg#, temperature of #270 ^oC#, and a specific heat of #18 J/(kg*K)# is dropped into a container with #36 L # of water at #0^oC #. Does the water evaporate? If not, by how much does the water's temperature change?

##### 1 Answer

#### Answer:

Rise in the temperature of water

#### Explanation:

We know that in such interactions heat is gained by one and heat is lost is by the other.

Also that the heat gained/lost is given by

where

Also from Law of conservation of energy:

In the given problem heat is lost by object and gained by water. Let the final temperatuer of the mixture be

Heat lost by object to cool down from

Heat gained by water to change from

Specific heat of water is

Equating (1) and (2) and solving for the required quantity

or

or