# An object with a mass of 3 kg is hanging from a spring with a constant of 8 (kg)/s^2. If the spring is stretched by 8 m, what is the net force on the object?

Mar 10, 2017

The net force is $= 34.6 N$ acting upwards

#### Explanation:

Let's resolve in the vertical direction ${\uparrow}^{+}$

${F}_{1} = k x = 8 \cdot 8 = 64 N$

${F}_{2} = - 3 g = - 3 g = - 29.4 N$

The net force is

$F = {F}_{1} + {F}_{2} = 64 - 29.4 = 34.6 N$

The force is acting upwards,