# An object with a mass of #4 g# is dropped into #650 mL# of water at #0^@C#. If the object cools by #12 ^@C# and the water warms by #30 ^@C#, what is the specific heat of the material that the object is made of?

##### 2 Answers

#### Answer:

#### Explanation:

Use Heat and the First Law of Thermodynamics. We can use the relationship

Divide equation (1) into (2) knowing that

Now what the mass of 650 ml of water? The mass of 650 ml of water is

Now is a question calculating. That said I am a bit suspicious of the answer it is too large for a specific heat value...

#### Answer:

Specific heat of material of object

The value is unrealistically high.

#### Explanation:

As the quantities have been given in CGS units, therefore, answer has been worked out in same units.

Value used

Specific heat of water

Let the specific heat of the material of object

Amount of heat exchanged is given as

where

Heat gained by

assuming

Simlarly heat lost by object is given as

Since,

or