Question

An object with a mass of `4 kg` is hanging from a spring with a constant of `2 (kg)/s^2`. If the spring is stretched by `8 m`, what is the net force on the object?

Answer 1

`SigmaF=23.2N` downwards

Explanation:

We know two forces are involved, one from the mass, and one from pulling the spring.

`F_1=mg=4*9.81=39.24N` (the force pulling on the object)

`F_2=kDeltax=2*8=16N` (the force the the object exerts on the spring and vice versa)

We know that `F_1` acts downwards, and `F_2` acts upwards.

`SigmaF=F_1-F_2=39.24-16=23.24~~23.2N` downwards