An object with a mass of $4 kg$ is hanging from a spring with a constant of $2 (kg)/s^2$ . If the spring is stretched by $18 m$ , what is the net force on the object?

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Answer 1 · 2017-06-02T14:49:01

The net force is $=3.2N$ acting downwards

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Mass of object $m=4kg$

The spring constant is $k=2kgs^-2$

Extension of the spring is $x=18m$

Resolving in the vertical direction $uarr^+$

The net force is $F=2*18-4g$

$=36-4g=-3.2N$

There is a net force of $3.2N$ acting downwards

An object with a mass of 4 kg4 kg is hanging from a spring with a constant of 2 (kg)/s^22 (kg)/s^2. If the spring is stretched by 18 m 18 m, what is the net force on the object?