Question

An object with a mass of `4 kg` is hanging from a spring with a constant of `3 (kg)/s^2`. If the spring is stretched by `6 m`, what is the net force on the object?

Answer 1

`F_n=21,24 " N"`

Explanation:

`G=m*g`
`G=4*9,81=39,24 N" Object's weight"`
`F=-k*Delta x`
`F=-3*6=-18 " N Force acting on spring"`
`F_n=G+F`
`F_n=39,24-18`
`F_n=21,24 " N"`