# An object with a mass of 40 g is dropped into 350 mL of water. If the object cools by 25 ^@C and the water warms by 10 ^@C, what is the specific heat of the material that the object is made of?

May 26, 2017

$3.5$ Cal per gram per degrees Celsius

#### Explanation:

${m}_{w a t e r} \cdot {C}_{w a t e r} \cdot \Delta T = {m}_{o b j e c t} \cdot {C}_{o b j e c t} \cdot \Delta T$

$350 \cdot 1 \cdot 10 = 40 \cdot {C}_{o b j e c t} \cdot 25$

${C}_{o b j e c t} = \frac{3500}{40 \cdot 25}$

${C}_{o b j e c t} = 3.5$ $\frac{C a l}{g \cdot \mathrm{de} g r e e s C}$

${C}_{o b j e c t} = 3.5$ $\frac{C a l}{g \cdot \mathrm{de} g r e e s C}$