An object with a mass of 5 kg is hanging from a spring with a constant of 3 (kg)/s^2. If the spring is stretched by 6 m, what is the net force on the object?

May 3, 2017

The net force is $= 31 N$

Explanation:

Mass of object $m = 5 k g$

The spring constant is $k = 3 k g {s}^{-} 2$

Extension of the spring is $x = 6 m$

Resolving in the vertical direction ${\uparrow}^{+}$

The net force is $F = 6 \cdot 3 - 5 g$

$= 18 - 5 g = - 31 N$

There is a net force of $31 N$ acting downwards