# An object with a mass of 5 kg is hanging from a spring with a constant of 3 (kg)/s^2. If the spring is stretched by 2 m, what is the net force on the object?

Apr 18, 2018

${\vec{F}}_{n e t} = 44 N$

#### Explanation:

As the ball is pulled by a distance $x$, a restoring force ${\vec{F}}_{s p r i n g} = k x$ acts on the ball and pulls it in the upward direction.

The weight of the ball $m \vec{g}$ acts in the downward direction.

Therefore the net force

$\text{ } {\vec{F}}_{n e t} = m \vec{g} - {\vec{F}}_{s p r i n g}$

$\Rightarrow \text{ } {\vec{F}}_{n e t} = m \vec{g} - k x$

$\Rightarrow \text{ } {\vec{F}}_{n e t} = 5 \times 10 - 3 \times 2$

$\Rightarrow \text{ } {\vec{F}}_{n e t} = 44 N$