Question

An object with a mass of `6 kg` is hanging from a spring with a constant of `12 (kg)/s^2`. If the spring is stretched by `12 m`, what is the net force on the object?

Answer 1

`Delta F=-647,46 N`

Explanation:

`"Gravity of mass :" G=m.g`
`G=6.9,81=58,86 N`
`"Force on spring :"F=12 .58,86=706,32`
`"Net Force :"58,86-706,32`
`Delta F=-647,46 N`