Question

An object with a mass of `6 kg` is hanging from a spring with a constant of `12 (kg)/s^2`. If the spring is stretched by `19 m`, what is the net force on the object?

Answer 1

The gravitational pull on the body of mass 6 kg is `mg=6xx9.8N=58.8N`
The upward force on the body due to stretching of spring by 19 m is `F = kx =12(kg)/s^2xx19m=228N`

Hence net upward force on the body= `228-58.8=169.2N`