An object with a mass of #6 kg# is hanging from a spring with a constant of #12 (kg)/s^2#. If the spring is stretched by # 29 m#, what is the net force on the object?
The net force is 289.2 N upward.
Giving a spring's constant in units of
From Newton's 2nd Law, we can see that
the Newton, N, is equivalent to
An algebraic operation shows us that
Using that last equivalency on the spring constant given as
it can be reworked as follows
OK, my rant is over.
If the spring is stretched by 29 m, the spring's force is given by
That force would be upward.
The mass's weight is a force downward. The value of that weight is
The net force is the vector sum of the spring's force and the mass's weight
This mass is apparently in a cycle of bouncing up and down on the spring.
I hope this helps,