# An object with a mass of #6 kg# is hanging from a spring with a constant of #12 (kg)/s^2#. If the spring is stretched by # 29 m#, what is the net force on the object?

##### 1 Answer

The net force is 289.2 N upward.

#### Explanation:

Giving a spring's constant in units of

From Newton's 2nd Law, we can see that

the Newton, N, is equivalent to

An algebraic operation shows us that

Using that last equivalency on the spring constant given as

it can be reworked as follows

OK, my rant is over.

If the spring is stretched by 29 m, the spring's force is given by

That force would be upward.

The mass's weight is a force downward. The value of that weight is

The net force is the vector sum of the spring's force and the mass's weight

This mass is apparently in a cycle of bouncing up and down on the spring.

I hope this helps,

Steve