# An object with a mass of 6 kg is hanging from a spring with a constant of 4 (kg)/s^2. If the spring is stretched by 9 m, what is the net force on the object?

What happens when you stretch the string and release, is that,the restoring force tries to pull the object upwards with the force (F= K×x=4×9=36 N)
So, net force acting on the object becomes $\left(m g - F\right)$ i.e (6×10-36) N or $24 N$ downwards.