An object with a mass of #6 kg# is hanging from a spring with a constant of #4 (kg)/s^2#. If the spring is stretched by #18 m#, what is the net force on the object?

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Answer 1 · 2017-02-22T10:07:38

The net force is #-13.2N# (acting upwards)

We resolve in the vertical direction #darr_+#

The weight acts downwards

#vecF_1=6g=6*9.8=58.8N#

According to Hooke's Law

#vecF_2=-kx#

#=-4*18=-72N#

The net force is

#vecF=vecF_1+vecF_2=58.8-72=-13.2N#