# An object with a mass of 6 kg is hanging from a spring with a constant of 4 (kg)/s^2. If the spring is stretched by 12 m, what is the net force on the object?

Jul 29, 2017

The net force on the object is $= 10.8 N$ acting downwards

#### Explanation:

Resolving in the direction ${\downarrow}_{+}$

The weight is $= \left(m g\right) N$

The force in the spring is $= \left(k \Delta x\right) N$

The spring constant is $k = 4 k g {s}^{-} 2$

The elongation is $\Delta x = 12 m$

The mass is $m = 6 k g$

The net force is

$= m g - k \Delta x$

$= 6 g - 4 \cdot 12$

$= 10.8 N$