# An object with a mass of 7 kg is hanging from a spring with a constant of 2 (kg)/s^2. If the spring is stretched by  9 m, what is the net force on the object?

Nov 11, 2016

The net force is $52 N$

#### Explanation:

The force due to the elongation of the spring is $= k x$
where $k =$is the spring constant and $x$, the elongation.
The weight of the object, acting downwards $= m g = 70 N$
THe force acting upwards, due to the spring $= 9 \cdot 2 = 18 N$

So the net force $= 70 - 18 = 52 N$ acting downwards