Question

An object with a mass of `7 kg` is hanging from a spring with a constant of `2 (kg)/s^2`. If the spring is stretched by `9 m`, what is the net force on the object?

Answer 1

The net force is `52 N`

Explanation:

The force due to the elongation of the spring is `=kx`
where `k=`is the spring constant and `x`, the elongation.
The weight of the object, acting downwards `=mg=70 N`
THe force acting upwards, due to the spring `=9*2=18 N`

So the net force `=70-18=52 N` acting downwards