An object with a mass of 7 kg is hanging from a spring with a constant of 3 (kg)/s^2. If the spring is stretched by  12 m, what is the net force on the object?

Mar 8, 2017

The net force is $= 32.6 N$ acting downwards

Explanation:

Let's resolve in the vertical direction ${\uparrow}^{+}$

${F}_{1} = k x = 3 \cdot 12 = 36 N$

${F}_{2} = - m g = - 7 g = - 68.6 N$

The net force is

$F = {F}_{1} + {F}_{2} = 36 - 68.6 = - 32.6 N$

The force is acting downwards,