An object with a mass of #8 kg# is moving at #5 m/s# over a surface with a kinetic friction coefficient of #6 #. How much power will it take to accelerate the object at #18 m/s^2?

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Answer 1 · 2017-04-05T11:34:36

The power is #=3072W#

The mass is #=8kg#

The coefficient of kinetic friction is #mu_k=6#

But,

#mu_k=F_k/N#

#N=mg=8g#

so,

#F_k=mu_k*N=6*8g=48g#

The force necessary to accelerate the object is

#F-F_k=ma#

#F=8*18+48g=614.4N#

The power is

#P=F*v=614.4*5=3072W#