An object with a mass of #8 kg# is moving at #5 m/s# over a surface with a kinetic friction coefficient of #6 #. How much power will it take to accelerate the object at #3 m/s^2?

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Answer 1 · 2017-06-02T12:42:20

The power is #=2472W#

The normal reaction is N #=mg=8gN#

The frictional force

# F_r = mu_k # N

#F_r=6*8g N#

Let the force necessary to accelerate the object be #F#

Then,

#F-F_r=m*a#

#F=F_r+m*a#

#=48g+8*3#

#=494.4N#

The power is

#P=Fv#

#=494.4*5#

#=2472W#