# An unknown compound is analyzed and found to be composed of 14.79% nitrogen, 50.68% oxygen, and 34.53% zinc. What is the empirical formula for the compound?

##### 2 Answers

The empirical formula is

#### Explanation:

To begin, using a

Your values will look like this :

#"14.79 g "# nitrogen#"50.68 g "# oxygen#"34.53 g "# zinc

Next, convert each value into moles by using molar mass.

(Divide your original value by the molar mass to find moles)

Take your smallest value of moles and divide every numerical value by it. In this case, the smallest value is

To find the smallest whole number ratio, multiply each value by

Your formula is now:

Remember, empirical formulas are related by a whole number ratios or the least common multiple of all numbers.

The empirical formula is:

(Remember that if the subscript of an element is

#### Explanation:

As always we ASSUME a

And so we divide thru by the SMALLEST molar quantity to get a trial empirical formula of...

And of course this is zinc nitrate...