Anyone knows the derivative of [ln(sec x tan x)^2]^2 ?

1 Answer
Sonnhard
Jun 9, 2018

#4ln(sec(x)tan(x))^2*ln(sec(x)*tan(x))*(sec(x)^3+sec(x)*tan(x))#

Explanation:

Using the chain and the power rule and that
#(sec(x)*tan(x))'=sec(x)^3+sec(x)tan(x)#
so we get

#2ln(sec(x)tan(x))^2*2ln(sec(x)tan(x))*(sec(x)^3+sec(x)*tan(x))#

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