Question

Approximating value with linearization?

`app. e^0.1`

Answer 1

1.1

Explanation:

By definition:

`e^x= sum_(k=0)^(oo) x^k/(k!) = 1 + x + mathbb O (x^2)`

Linearizing:

`e^(0.1) approx 1+ 0.1 = 1.1`