Are the lines #y=8x-5, y=1/8x+1# and #8x+y=2# parallel or perpendicular?

1 Answer

The second and third lines are perpendicular

Explanation:

If you restructure the third equation by subtracting #8x# from both sides, you'll get

#y=-8x+2#

With

#y=mx+b" "# [here #m = #slope]

you know the slope of all three lines: #8#, #1/8#, and #-8#, respectively.

Two lines are perpendicular when their slopes are negative reciprocals . You can see that two slopes are negative reciprocals if #-1# divided by one slope equals the other slope.

Because #-1# divided by #-8# equals #1/8#, you know that the second and third equations have negative reciprocal slopes, therefore they are perpendicular.

The first equation isn't perpendicular to either of the other two lines because #-1# divided by #8# is #-1/8#, which does not match any of the other slopes. It isn't parallel either (parallel lines have the same slope).