Assume that the random variable #X# is normally distributed, with mean = 50 and standard deviation = 7. How would I compute the probability #P( X > 35 )#?

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Answer 1 · 2017-05-09T16:22:20

#P(Z> -2.14)=0.9838#

#X~N(50,7^2)#

#P(X>35)#

standardising

#P(X>35)rarrP(Z>(35-50)/7)#

#=P(Z> -2.14)" ( 2dps)#

now by the symmetry of the Normal curve

#P(Z> -2.14)=P(Z<2.14)#

so we now look up directly from tables

#P(Z> -2.14)=0.9838#