Question

Assume that z-scores are normally distributed with a mean of 0 and a standard deviation of 1. If `P(-d < z < d)=0.4844`, how do you find `d`?

Answer 1

`P(-d < z < d) = 0.4844` is represented by the area about mean.
It implies that `0.4844/2 = 0.2422` is the area each on the left side and right side of mean.

The z value corresponding to `0.2422` area is `0.65`

Therefore, `d = 0.65`

`[P(-d < z < d) = P(- 0.65 < z < 0.65) = 0.4844]`