# At constant pressure, what temperature must be reached to increase a 100-milliliter sample of a gas initially at 300 K to a volume of 200 milliliters?

Jan 25, 2016

The new temperature is 600 K.

#### Explanation:

Given

The volume ${V}_{1}$ of a gas at a temperature ${T}_{1}$.
A second volume ${V}_{2}$.

Find

The second temperature ${T}_{2}$.

Strategy

A problem involving two gas volumes and two temperatures must be a Charles' Law problem.

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

${V}_{1} = \text{100 mL}$; ${T}_{1} = \text{300 K}$
${V}_{2} = \text{200 mL}$; ${T}_{2} = \text{?}$
${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$
T_2 = T_1 × V_2/V_1 = "300 K" × (200 cancel("mL"))/(100 cancel("mL")) = "600 K"