At this instant, find the radial acceleration?

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1 Answer
Jane
Feb 28, 2018

See the direction of acceleration shown in the picture of this question,shows the direction of net acceleration,which can be represented as the vector sum of tangential and radial acceleration.enter image source here

Now,we know,radial acceleration at any point = #v^2/r# where, #v# is the velocity at that point and let, tangential acceleration be #a'#,

So,we can write, #sqrt((v^2/r)^2 + a'^2) = 16 #

And, #tan 30 = (a') /(v^2/r)#

Given, #r=2.50#

so, our two equations become,

#(v^2/(2.50))^2 + a'^2 =256# ....1

and, #a'= v^2/(2.50)1/sqrt(3)#...2

Solving both,we get, #v=5.87 ms^-1#

And, #a'=7.96 ms^-1#

So, radial acceleration = #v^2/r=13.77 ms^-2#

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