# At what temperature in Celsius will 19.4 g of molecular Ozone exert a pressure of 1820 mmHg in a 5.12 L cylinder?

##### 2 Answers

#### Answer:

#### Explanation:

Ozone =

Molar mass =

No. of moles =

Pressure =

P =

Volume = 5.12 L

R = 0.08206 atm.L.K-1.mol-1

According to ideal gas law

#### Answer:

The temperature in degrees Celsius is

#### Explanation:

You will need to use the ideal gas law in order to answer this question. The formula is:

where P is pressure, V is volume, n is moles, R is the gas constant, and T is temperature in Kelvins.

**Determine Moles #"O"_3#**

In order to determine the moles of molecular ozone

https://www.ncbi.nlm.nih.gov/pccompound?term=ozone

**Gas Constant, #R#**

The gas constant is determined by the units used in the question. The pressure is in mmHg, the volume is in liters (L), the quantity is in moles (n), and the temperature is in Kelvins (K).

https://en.wikipedia.org/wiki/Gas_constant (1 Torr=1 mmHg)

**Organize the data:**

**Known**

**Unknown**

**Solution**

Rearrange the equation to isolate

**Convert Temperature from Kelvins to degrees Celsius**

Subtract